Determine whether a number is a perfect number an armstrong number or a palindrome Python Program

Determine whether a number is a perfect number an armstrong number or a palindrome Python Program

 

# Palindrome (12321 is Palindrome)
number=int(input("Enter any number:"))
num=number
num1= number
rev=0
while num>0:
    digit=num%10
    rev=rev*10+digit
    num=int(num/10)
if number==rev:
    print(number ,'is a Palindrome')
else:
    print(number , 'Not a Palindrome')

# Armstrong number is equal to sum of cubes of each digit
sum = 0
temp = num1
while temp > 0:
   digit = temp % 10
   sum += digit ** 3
   temp //= 10
if num1 == sum:
   print(num1," is an Armstrong number")
else:
   print(num1," is not an Armstrong number")

# Perfect number, a positive integer that is equal to the sum of its proper divisors.

sum1 = 0
for i in range(1, number):
    if(number % i == 0):
        sum1 = sum1 + i
if (sum1 == number):
    print(number, " The number is a Perfect number")
else:
    print(number, " The number is not a Perfect number")

 

 

Output:

Enter any number:12321
(12321, 'is a Palindrome')
(12321, ' is not an Armstrong number')
(12321, ' The number is not a Perfect number')

 

 

Enter any number:2356
(2356, 'Not a Palindrome')
(2356, ' is not an Armstrong number')
(2356, ' The number is not a Perfect number')
>>> 



Enter any number:153
(153, 'Not a Palindrome')
(153, ' is an Armstrong number')
(153, ' The number is not a Perfect number')
>>>

 

 

Enter any number:6
(6, 'is a Palindrome')
(6, ' is not an Armstrong number')
(6, ' The number is a Perfect number')
>>>

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